Interop namespace MyApp īy registering the Java class and mapping it to the C# class, Xamarin will be able to create the necessary JavaTypeInfo and resolve the error. This method takes two parameters: the Java class name and the C# type. Use the method to register the Java class and map it to the C# class. This class should have the same name, namespace, and properties as the Java class. This can be found in the build output or the error message.Ĭreate a C# class that matches the Java class. Identify the Java class that is causing the error. This can be done by using the class, which provides methods to register Java types and map them to C# types. One possible solution to fix the "failed to create JavaTypeInfo for class" error in Xamarin is to check for mismatched Java and C# types. Method 1: Check for mismatched Java and C# types The issue arises due to various reasons, including mismatched Java and C# types, missing dependencies, or incorrect class references. This error occurs when the Xamarin build process encounters a conflict between the C# code and the Java code used by Android. The "failed to create JavaTypeInfo for class" error is a common issue faced by Xamarin developers when building an Android app using C#.
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